--- description: 'Disallow calling a function with a value with type `any`.' --- > 🛑 This file is source code, not the primary documentation location! 🛑 > > See **https://typescript-eslint.io/rules/no-unsafe-argument** for documentation. The `any` type in TypeScript is a dangerous "escape hatch" from the type system. Using `any` disables many type checking rules and is generally best used only as a last resort or when prototyping code. Despite your best intentions, the `any` type can sometimes leak into your codebase. Calling a function with an `any` typed argument creates a potential safety hole and source of bugs. This rule disallows calling a function with `any` in its arguments. That includes spreading arrays or tuples with `any` typed elements as function arguments. This rule also compares generic type argument types to ensure you don't pass an unsafe `any` in a generic position to a receiver that's expecting a specific type. For example, it will error if you pass `Set` as an argument to a parameter declared as `Set`. ## Examples ### ❌ Incorrect ```ts declare function foo(arg1: string, arg2: number, arg3: string): void; const anyTyped = 1 as any; foo(...anyTyped); foo(anyTyped, 1, 'a'); const anyArray: any[] = []; foo(...anyArray); const tuple1 = ['a', anyTyped, 'b'] as const; foo(...tuple1); const tuple2 = [1] as const; foo('a', ...tuple, anyTyped); declare function bar(arg1: string, arg2: number, ...rest: string[]): void; const x = [1, 2] as [number, ...number[]]; foo('a', ...x, anyTyped); declare function baz(arg1: Set, arg2: Map): void; foo(new Set(), new Map()); ``` ### ✅ Correct ```ts declare function foo(arg1: string, arg2: number, arg3: string): void; foo('a', 1, 'b'); const tuple1 = ['a', 1, 'b'] as const; foo(...tuple1); declare function bar(arg1: string, arg2: number, ...rest: string[]): void; const array: string[] = ['a']; bar('a', 1, ...array); declare function baz(arg1: Set, arg2: Map): void; foo(new Set(), new Map()); ``` There are cases where the rule allows passing an argument of `any` to `unknown`. Example of `any` to `unknown` assignment that are allowed: ```ts showPlaygroundButton declare function foo(arg1: unknown, arg2: Set, arg3: unknown[]): void; foo(1 as any, new Set(), [] as any[]); ``` ## When Not To Use It If your codebase has many existing `any`s or areas of unsafe code, it may be difficult to enable this rule. It may be easier to skip the `no-unsafe-*` rules pending increasing type safety in unsafe areas of your project. You might consider using [ESLint disable comments](https://eslint.org/docs/latest/use/configure/rules#using-configuration-comments-1) for those specific situations instead of completely disabling this rule. ## Related To - [`no-explicit-any`](./no-explicit-any.md) - [`no-unsafe-assignment`](./no-unsafe-assignment.md) - [`no-unsafe-call`](./no-unsafe-call.md) - [`no-unsafe-member-access`](./no-unsafe-member-access.md) - [`no-unsafe-return`](./no-unsafe-return.md)